发布网友
共1个回答
热心网友
az/ax
=1/cos(x-2y) ·(-sin(x-2y))·1
=-tan(x-2y)
az/ay
=
=1/cos(x-2y) ·(-sin(x-2y))·(-2)
=2tan(x-2y)
热心网友
az/ax
=1/cos(x-2y) ·(-sin(x-2y))·1
=-tan(x-2y)
az/ay
=
=1/cos(x-2y) ·(-sin(x-2y))·(-2)
=2tan(x-2y)